22 Would be diametrically
opposite to 7. The process that I used to work on this problem was to relate it
to a similar situation, a clock. This question can be thought of as a clock
that goes to 30 instead of 12. On this special new 30-clock, every number is bigger than on a regular clock by a
factor of 30/12 or 5/2 or 2.5. So 7 on this clock would be 14/5 on a regular
clock, which is 2.8 or just before 3 o’clock. Thinking about the familiar clock, we can realize that diametrically opposite to just
before 3 o’clock, is just before 9 o’clock. The distance before 3 would be the same as the distance before 9. To be exact, it is 8.8 or 44/5 so on our new
30-clock, 44/5 would be 44/5 * 5/2 which is 22. So, 22 is diametrically opposed
to 7 on this 30 point circle.
I’m
torn on the issue of impossible questions because on the one hand, they may
inspire students, but on the other hand, they may repel students. While I don’t
doubt that a small number of students who are very curious about math may find
some joy and valuable contemplation in impossible questions, I believe that
most students would be disheartened by the prospect of an impossible question
and overall, impossible questions may turn more students off of math than they
would bring students towards it. There are many other ways to inspire curious math students. Therefore, this approach of impossible questions should probably be foregone or restricted to only the students interested in them, as it may result in the exclusion of some students.
When I
think of geometry, I think of shapes. So what makes a puzzle geometric (instead
of simply logical) is the involvement of shapes as a necessary aspect of the
puzzle. That being said, a geometric puzzle can often be solved by other means. Similarly, a non-geometric puzzle can sometimes be solved geometrically.
Fascinating solution, Ben! I hope you will be willing to share it in class today. I appreciate your really thoughtful ideas about impossible problems too.
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